Optimal. Leaf size=330 \[ -\frac {\sec ^3(c+d x) (b-8 a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{30 d}+\frac {\sec ^5(c+d x) (b+a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{5 d}-\frac {a \left (32 a^2-29 b^2\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{60 \left (a^2-b^2\right ) d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}+\frac {\left (32 a^2-5 b^2\right ) F\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{60 d \sqrt {a+b \sin (c+d x)}}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (b \left (8 a^4-13 a^2 b^2+5 b^4\right )-a \left (32 a^4-61 a^2 b^2+29 b^4\right ) \sin (c+d x)\right )}{60 \left (a^2-b^2\right )^2 d} \]
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Rubi [A]
time = 0.45, antiderivative size = 330, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 7, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.304, Rules used = {2770, 2945,
2831, 2742, 2740, 2734, 2732} \begin {gather*} \frac {\left (32 a^2-5 b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} F\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{60 d \sqrt {a+b \sin (c+d x)}}-\frac {a \left (32 a^2-29 b^2\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{60 d \left (a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (b \left (8 a^4-13 a^2 b^2+5 b^4\right )-a \left (32 a^4-61 a^2 b^2+29 b^4\right ) \sin (c+d x)\right )}{60 d \left (a^2-b^2\right )^2}+\frac {\sec ^5(c+d x) (a \sin (c+d x)+b) \sqrt {a+b \sin (c+d x)}}{5 d}-\frac {\sec ^3(c+d x) (b-8 a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{30 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 2732
Rule 2734
Rule 2740
Rule 2742
Rule 2770
Rule 2831
Rule 2945
Rubi steps
\begin {align*} \int \sec ^6(c+d x) (a+b \sin (c+d x))^{3/2} \, dx &=\frac {\sec ^5(c+d x) (b+a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{5 d}-\frac {1}{5} \int \frac {\sec ^4(c+d x) \left (-4 a^2+\frac {b^2}{2}-\frac {7}{2} a b \sin (c+d x)\right )}{\sqrt {a+b \sin (c+d x)}} \, dx\\ &=-\frac {\sec ^3(c+d x) (b-8 a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{30 d}+\frac {\sec ^5(c+d x) (b+a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{5 d}+\frac {\int \frac {\sec ^2(c+d x) \left (\frac {1}{4} \left (32 a^4-37 a^2 b^2+5 b^4\right )+6 a b \left (a^2-b^2\right ) \sin (c+d x)\right )}{\sqrt {a+b \sin (c+d x)}} \, dx}{15 \left (a^2-b^2\right )}\\ &=-\frac {\sec ^3(c+d x) (b-8 a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{30 d}+\frac {\sec ^5(c+d x) (b+a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{5 d}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (b \left (8 a^4-13 a^2 b^2+5 b^4\right )-a \left (32 a^4-61 a^2 b^2+29 b^4\right ) \sin (c+d x)\right )}{60 \left (a^2-b^2\right )^2 d}-\frac {\int \frac {\frac {1}{8} b^2 \left (8 a^4-13 a^2 b^2+5 b^4\right )+\frac {1}{8} a b \left (32 a^4-61 a^2 b^2+29 b^4\right ) \sin (c+d x)}{\sqrt {a+b \sin (c+d x)}} \, dx}{15 \left (a^2-b^2\right )^2}\\ &=-\frac {\sec ^3(c+d x) (b-8 a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{30 d}+\frac {\sec ^5(c+d x) (b+a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{5 d}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (b \left (8 a^4-13 a^2 b^2+5 b^4\right )-a \left (32 a^4-61 a^2 b^2+29 b^4\right ) \sin (c+d x)\right )}{60 \left (a^2-b^2\right )^2 d}-\frac {\left (a \left (32 a^2-29 b^2\right )\right ) \int \sqrt {a+b \sin (c+d x)} \, dx}{120 \left (a^2-b^2\right )}-\frac {1}{120} \left (-32 a^2+5 b^2\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}} \, dx\\ &=-\frac {\sec ^3(c+d x) (b-8 a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{30 d}+\frac {\sec ^5(c+d x) (b+a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{5 d}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (b \left (8 a^4-13 a^2 b^2+5 b^4\right )-a \left (32 a^4-61 a^2 b^2+29 b^4\right ) \sin (c+d x)\right )}{60 \left (a^2-b^2\right )^2 d}-\frac {\left (a \left (32 a^2-29 b^2\right ) \sqrt {a+b \sin (c+d x)}\right ) \int \sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}} \, dx}{120 \left (a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {\left (\left (-32 a^2+5 b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}\right ) \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}} \, dx}{120 \sqrt {a+b \sin (c+d x)}}\\ &=-\frac {\sec ^3(c+d x) (b-8 a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{30 d}+\frac {\sec ^5(c+d x) (b+a \sin (c+d x)) \sqrt {a+b \sin (c+d x)}}{5 d}-\frac {a \left (32 a^2-29 b^2\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{60 \left (a^2-b^2\right ) d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}+\frac {\left (32 a^2-5 b^2\right ) F\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{60 d \sqrt {a+b \sin (c+d x)}}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (b \left (8 a^4-13 a^2 b^2+5 b^4\right )-a \left (32 a^4-61 a^2 b^2+29 b^4\right ) \sin (c+d x)\right )}{60 \left (a^2-b^2\right )^2 d}\\ \end {align*}
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Mathematica [A]
time = 6.28, size = 364, normalized size = 1.10 \begin {gather*} \frac {\sqrt {a+b \sin (c+d x)} \left (\frac {1}{5} \sec ^5(c+d x) (b+a \sin (c+d x))+\frac {1}{30} \sec ^3(c+d x) (-b+8 a \sin (c+d x))+\frac {\sec (c+d x) \left (-8 a^2 b+5 b^3+32 a^3 \sin (c+d x)-29 a b^2 \sin (c+d x)\right )}{60 \left (a^2-b^2\right )}\right )}{d}-\frac {b \left (-\frac {2 \left (8 a^2 b-5 b^3\right ) F\left (\frac {1}{2} \left (-c+\frac {\pi }{2}-d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{\sqrt {a+b \sin (c+d x)}}-\frac {\left (32 a^3-29 a b^2\right ) \left (\frac {2 (a+b) E\left (\frac {1}{2} \left (-c+\frac {\pi }{2}-d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{\sqrt {a+b \sin (c+d x)}}-\frac {2 a F\left (\frac {1}{2} \left (-c+\frac {\pi }{2}-d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{\sqrt {a+b \sin (c+d x)}}\right )}{b}\right )}{120 (a-b) (a+b) d} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(1518\) vs.
\(2(372)=744\).
time = 3.00, size = 1519, normalized size = 4.60
method | result | size |
default | \(\text {Expression too large to display}\) | \(1519\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.15, size = 612, normalized size = 1.85 \begin {gather*} \frac {\sqrt {2} {\left (64 \, a^{4} - 82 \, a^{2} b^{2} + 15 \, b^{4}\right )} \sqrt {i \, b} \cos \left (d x + c\right )^{5} {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) - 3 i \, b \sin \left (d x + c\right ) - 2 i \, a}{3 \, b}\right ) + \sqrt {2} {\left (64 \, a^{4} - 82 \, a^{2} b^{2} + 15 \, b^{4}\right )} \sqrt {-i \, b} \cos \left (d x + c\right )^{5} {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) + 3 i \, b \sin \left (d x + c\right ) + 2 i \, a}{3 \, b}\right ) + 3 \, \sqrt {2} {\left (32 i \, a^{3} b - 29 i \, a b^{3}\right )} \sqrt {i \, b} \cos \left (d x + c\right )^{5} {\rm weierstrassZeta}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) - 3 i \, b \sin \left (d x + c\right ) - 2 i \, a}{3 \, b}\right )\right ) + 3 \, \sqrt {2} {\left (-32 i \, a^{3} b + 29 i \, a b^{3}\right )} \sqrt {-i \, b} \cos \left (d x + c\right )^{5} {\rm weierstrassZeta}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) + 3 i \, b \sin \left (d x + c\right ) + 2 i \, a}{3 \, b}\right )\right ) - 6 \, {\left ({\left (8 \, a^{2} b^{2} - 5 \, b^{4}\right )} \cos \left (d x + c\right )^{4} - 12 \, a^{2} b^{2} + 12 \, b^{4} + 2 \, {\left (a^{2} b^{2} - b^{4}\right )} \cos \left (d x + c\right )^{2} - {\left ({\left (32 \, a^{3} b - 29 \, a b^{3}\right )} \cos \left (d x + c\right )^{4} + 12 \, a^{3} b - 12 \, a b^{3} + 16 \, {\left (a^{3} b - a b^{3}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )} \sqrt {b \sin \left (d x + c\right ) + a}}{360 \, {\left (a^{2} b - b^{3}\right )} d \cos \left (d x + c\right )^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a+b\,\sin \left (c+d\,x\right )\right )}^{3/2}}{{\cos \left (c+d\,x\right )}^6} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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